Question

1. If x + y = 12 and xy = 32, Find the value of x2

+ y2

.

Answer 1

square on both side 
so
(x+y)²=(12)²
x²+y²+2xy=144
putt the value 
x²+y²+2*32=144
x²+y²+64=144
x²+y²=144-64
x²+y²=80






i hope this will help u 
by DEVANSH

Answer 2

Step-by-step explanation:

given =.x+y = 12

xy=32

find $x^{2}+y^{2}=?$

x+y = 12 (squaring on both side)

$x^{2}+y^{2}+ 2xy = 144 \\ x^{2}+y^{2}+2×32 = 144 \\ x^{2}+y^{2}=.144-2×32 \\ x^{2}+y^{2}=80$

....hope.this will help