Question

1. If x+y+z=0, then find (x+y)3+(y+z)3+(Z+x)3.​

Answer 1

Answer:

its value will also be zero.

Step-by-step explanation:

we can use the formula of A3+B3+C3=(a+b+c)(A2+b2+c2-2(ab+bc+ca)

Answer 2

Answer:

let x+y=a, y+z=b, z+x= c

a+b+c=2(x+y+z) =2×0=0

so, a³+b³+c³= 3abc -(a+b+c) (a²+b²+c² +ab+bc+ca)

put value a+b+c=0

a³+b³+c³=3abc

=3(x+y) (y+z) (z+x)