1. If x²+2x-1 is divided by x+1, the remainder is
2. The value of √n, where n is an even positive integer, is
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for finding the remainder we need to use remainder theorom
let p(x)=x^2+2x+1
Here, the divisor is x+1 for dividend p(x), we need to equate it to 0 and put that value of x in p(x).
−x+1=0
∴x=−1
p(−1)=(−1)^2+2(−1)+1=0
Hence, remainder=0
I hope it will help you army ☺️✌️
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