Question

1.In 10s, a charge of 25C leaves a battery, and 200J of energy are delivered to an outside circuit as a result.

a) What is the p.d. across the battery?

b)What current flos from the battery?

2.An electric heater is connected to the 230V mains supply. A current of 8 A flows through the heater.

a) How much charge flows around the circuit each second?

b) How much energy is transferred to the heater each second?

Answer 1

1a)p.d=work done/total charge=1J/1C=200J/25C=8V
b)1A=1C/1S=25C/10S=2.5A
2a)charge=current*time =8A*1s=8C
b)work or energy=pd*Q=230V*8C=1840J

Answer 2

(1) (a) V = 8 volts

(b) I = 2.5 A

(2) (a) q = 8 C

(b) W =1840 J

Explanation:

(1) Given that, in 10 s, a charge of 25 C leaves a battery, and 200 J of energy are delivered to an outside circuit as a result.

(a) The potential difference between the batteries is given by work done per unit electric charge.  

$V=\dfrac{W}{q}\\\\V=\dfrac{200\ J}{25\ C}\\\\V=8\ V$

(b) The current flowing through the circuit is given by total charge per unit time. Such that,

$I=\dfrac{q}{t}\\\\I=\dfrac{25}{10}\\\\I=2.5\ A$

(2) An electric heater is connected to the 230 V mains supply. A current of 8 A flows through the heater.

(a) Current,

$I=\dfrac{q}{t}\\\\q=I\times t\\\\q=8\ C$

So, the 8 C of charge flows around the circuit each second

(b) Electric potential is given by :

$V=\dfrac{W}{q}\\\\W=E=V\times q\\\\W=230\times 8\\\\W=1840\ J$

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