Question

1. In A ABC, right-angled at B, AB= 24 cm, BC = 7 cm. Determine:
(1) sin A, cos A
(ü) sin C, cos C​

Answer 1

In ∆ ABC, AB = 24cm, BC = 7 cm. AC = ?

↪ By using Pythagoras Theorem, we get the value of AC.

(HYPOTENUSE)² = (SIDE)² + (SIDE)²

➡ (AC)² = (BC)² + (AB)²

➡ (AC)² = (7)² + (24)²

➡ (AC)² = 49 + 576

➡ (AC)² = 625

➡ AC = √625

➡ AC = 25.

∴ AC = 25 cm.

(1) sin A, cos A

↪ sin A :

➡ sin A = opposite/hypotenuse

➡ sin A = BC/AC

➡ sin A = 7/25

↪ cos A :

➡ cos A = adjacent/hypotenuse

➡ cos A = AB/AC

➡ cos A = 24/25

(2) sin C, cos C

↪ sin C :

➡ sin C = opposite/hypotenuse

➡ sin C = AB/AC

➡ sin C = 24/25

↪ cos C :

➡ cos C = adjacent/hypotenuse

➡ cos C = BC/AC

➡ cos C = 7/25

Hence, it is solved...

Step-by-step explanation:

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