Please solve Question no 9 and 10 ‘s 1 and 2.
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sorry bruh
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I didn't understand properly please share pic of question
anandaraorc:
the sum of quadrilateral =360,. x+45+75+140=360, x+260=360,. x-360=100,. last angle =100
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9th :- 45+75+140+x =360
x=360-260=100
10th:- 1- let angles be x,2x,3x,4x
x+2x+3x+4x=10x=360
x=36
angles are 36,72,108,144
10th :- 2- let angles be 2x,5x,5x,6x
2x+5x+5x+6x=18x=360
x=20
angles are 40,100,100,120
hope it helps
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I am from the city of taj and my name is vedant
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