1. IN A CERTAIN CODE LANGUAGE ' NATURAL ' IS WRITTEN AS ' UBOUMBS ' .HOW WILL ' PROBLEM BE WRITTEN IN THAT CODE LANGUAGE ?
A. QSPBMFN
B. QSPBNFM
C. PSQBNFM
D. PSQBMFN
2. SONALI DROVE HER CAR 20 KM NORTHWARD . THEN SHE TURNED LEFT AND DROVE FOR 30 KM . SHE THEN TURNED LEFT AGAIN AND DROVE YET ANOTHER 20 KM .AGAIN SHE TURNED LEFT AND DROVE HER CAR 45 KM . HOW FAR SHE WILL BE NOW FROM THE INITIAL POINT ?
A. 10 KM
B. 20 KM
C. 15 KM
D. 25 KM
GIVE ALL THE THREE ANSWERS WITH PROPER EXPLANATION .
Answers
Original letters Change Encrypted letter
N +7 U
A +1 B
T -5 O
U 0 U
R -5 M
A +1 B
L +7 S
Pattern obtained = +7 +1 -5 0 -5 +1 +7
We have 4 sets of changes - +7,+1,-5,0 which are to be assigned a,b,c,d respectively.
So we take the word "PROBLEM"
if we encrypt the first letter in a similar pattern we will get 'W' which is not in any of the options.
Similarly, there is no change of -5
So we assign them to be either a or c
So we observe changes of +1 and 0 only
Now notice the change
1st and last letter of the encrypted "NATURAL" is encrypted in a same way, that is, +7 is added.
Hence from the four options, we clearly observe this change only in the first option.
Further on going through the pattern we will find a similar pattern as that of "NATURAL". Hence the answer is A. QSPBMFN
Let the initial Point be A So from the the car moves 20km north , taking it as B.From B it turned a sharp left and went 30km taking as C.From C another 20km was covered, taking it as D. And finally from D she turned left and covered 45km.
30km
C B
20km 20km
D A
45km
So if we observe closely, we would get a rectangle ABCD(BC=AD Since,opposite sides are equal in triangles)
Hence the distance from point D to A, that is, inital point is around 30km.
So the car did not stop at the initial point, it went further to cover another (45-30)km that is , 15km. So at present the car must be 30km towards East from the Initial point
Answer:
We are to relate the two words "NATURAL" AND "UBOUMBS"
Original letters Change Encrypted letter
N +7 U
A +1 B
T -5 O
U 0 U
R -5 M
A +1 B
L +7 S
Pattern obtained = +7 +1 -5 0 -5 +1 +7
We have 4 sets of changes - +7,+1,-5,0 which are to be assigned a,b,c,d respectively.
So we take the word "PROBLEM"
if we encrypt the first letter in a similar pattern we will get 'W' which is not in any of the options.
Similarly, there is no change of -5
So we assign them to be either a or c
So we observe changes of +1 and 0 only
Now notice the change
1st and last letter of the encrypted "NATURAL" is encrypted in a same way, that is, +7 is added.
Hence from the four options, we clearly observe this change only in the first option.
Further on going through the pattern we will find a similar pattern as that of "NATURAL". Hence the answer is A. QSPBMFN
Let the initial Point be A So from the the car moves 20km north , taking it as B.From B it turned a sharp left and went 30km taking as C.From C another 20km was covered, taking it as D. And finally from D she turned left and covered 45km.
30km
C B
20km 20km
D A
45km
So if we observe closely, we would get a rectangle ABCD(BC=AD Since,opposite sides are equal in triangles)
Hence the distance from point D to A, that is, inital point is around 30km.
So the car did not stop at the initial point, it went further to cover another (45-30)km that is , 15km. So at present the car must be 30km towards East from the Initial point