Math, asked by rahulyadav140596, 11 months ago

1-In a gram panchayat meeting, 1000 people on a resolution with 10 % of the votes being invalid. After some discussion 1000 people voted again. This time there were 20% invalid votes. The opponents were increased by 50% while the motion was now rejected by a majority, which is 300% more than it was formerly passed by. How many people voted against the resolution before the discussion? (a) 700 (b) 600 (c) 500 (d) 400 (e) None of these​

Answers

Answered by sonuvuce
16

Answer:

Option (d) 400

Step-by-step explanation:

10% of 1000 = 100

Therefore, first time, the no. of valid votes = 1000 - 100 = 900

Let the no. of people who voted against the resolution = x

Then the no. of people who voted for the resolution = 900 - x

The motion was passed by = 900 - x - x = 900 - 2x

When they voted again after discussion, 20% votes were invalid

Thus total valid votes = 1000 - 20% of 1000

                                   = 1000 - 20 × 1000/100

                                   = 1000 - 200

                                    = 800

50% increase in x = x + (50/100) × x

                              = x + x/2

                             = 3x/2

No. of people who voted for = 800 - 3x/2

Motion was rejected by = 3x/2 - (800 - 3x/2)

                                       = 3x - 800

Again,

The motion was rejected by = (900 - 2x) + (900 - 2x) × 300/100

                                             = (900 - 2x) + (900 - 2x) × 3

                                            = 4(900 - 2x)

Thus,

3x - 800 = 4(900 - 2x)

⇒ 3x - 800 = 3600 - 8x

⇒ 11x = 4400

⇒ x = 4400/11 = 400

Hope it helps.

Answered by AbhishekJaiswal1998
0

Answer:

400 is the correct answer

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