Question

1. In a triangle ABC, side AB is x cm, side BC is five more than side AB, and side AC is two times side BC. If the perimeter is 41 cm, find the value of x and each side.

2. A rectangle has a length one more than two times its width. The perimeter is 44 inches. Find the dimensions of the rectangle.

Answer 1

Answer:

1. According to question

AB= X

BC= 5+X

AC=2(5+X)

then, we know

AB+BC+AC=41

X+(5+X)+2(5+X)=41

X+5+X+10+2X= 41

4X+15=41

X=(41-15)/4

=26/4 cm