1. In a triangle ABC, side AB is x cm, side BC is five more than side AB, and side AC is two times side BC. If the perimeter is 41 cm, find the value of x and each side.
2. A rectangle has a length one more than two times its width. The perimeter is 44 inches. Find the dimensions of the rectangle.
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Answer:
1. According to question
AB= X
BC= 5+X
AC=2(5+X)
then, we know
AB+BC+AC=41
X+(5+X)+2(5+X)=41
X+5+X+10+2X= 41
4X+15=41
X=(41-15)/4
=26/4 cm
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