1. In ABC, AB = BC and B = 3 A, find A, B, C.
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Step-by-step explanation:
We can see that ∠A = ∠C [∵AB=AC]
∠A +∠C + ∠B = 180
∘
{∵ sum of all the angles of triangle is 180
o
}
so, 2∠C = 180
∘
- 64
∘
= 116
∘
(since ∠A = ∠C)
⇒∠C =
2
116
∘
=58
∘
⇒∠A = 58
∘
and ∠C = 58
∘
⇒∠C = 58
∘
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