1. In an experiment, suppose 10.0 g of potassium iodide was used with excess lead (II) nitrate & 9.50 g of precipitate was collected. Calculate the percentage yield of the reaction.(I already know how to do this but just for reference for second question)
2.In the previous example, 10.0 g of potassium iodide was reacted with lead (II) nitrate. What if the potassium iodide was only 85.0% pure? How much precipitate would we expect then?
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