Question

1. In cyclic quadrilateral ABCD, diagonals AC and BD intersect
at P. If angle DBC = 70° and angle BAC = 30°, then find angle BCD.​

Answer 1

Answer:

hope it will help

thanks

Answer 2

Step-by-step explanation:

<DBC=<DAC(angles in same segment)

70°=<DAC

<DAB+<BAC=180°(opposition angles are equal in cyclic quadrilateral)

<DAB=<DAC+<BAC

=70°+30°

<DAB=100°

<DAB+<BAC=180°

100°+<BAC=180°

<BAC=180-100

<BAC=80°