Question

1. In Fig. 9.15, ABCD is a parallelogram, AE 1 DC
and CF I AD. If AB = 16 cm, AE = 8 cm and
CF=10 cm, find AD.​

Answer 1

area of parallelogram is base into height and AB is equal to DC o area of the parallelogram is AE X DC = 16X8 and area of para. is also base x height = AD x FC = 10 X AD. now by comparing both the results we get AD is equal to 16 X 8 / 10 that is 12.8

hope it's help u

Answer 2

Question :-

In figure, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD.

Answer :-

We have, AE ⊥ DC and AB = 16 cm

∵ AB = CD [Opposite sides of parallelogram]

∴ CD = 16 cm

Now, area of parallelogram ABCD = CD x AE

= (16 x 8) cm2 = 128 cm2 [∵ AE = 8 cm]

Since, CF ⊥ AD

∴ Area of parallelogram ABCD = AD x CF

⇒ AD x CF = 128 cm

⇒ AD x 10 cm = 128 cm2 [∵ CF= 10 cm]

⇒ AD = 128/10 cm = 12.8 cm 10

Thus, the required length of AD is 12.8 cm

Hope it helps ❤ Mrk as brainliest