Question

1. In figure angleB<angleA and angleC<angleD. Show that AD<BC.
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Answer 1

Answer:

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Step-by-step explanation:

Let the point of intersection of BC and AD be O

In △ABO

⇒∠B<∠A

Thereore, ⇒AO<BO (1) (side opposite to greater angle is largest)

Similarly,

In △COD

⇒∠C<∠D

Thereore, ⇒DO<CO (2) (side opposite to greater angle is largest)

Adding (1) and (2) we get,

⇒BO+OC>AO+DO

⇒BC>AD