1. In figure. (i) and (ii), DE || BC. Find EC in (i) and AD in (ii).
Answers
Answered by
4
Answer:
i) Given, in △ ABC, DE∥BC
∴ AD/DB = AE/EC [Using Basic proportionality theorem]
⇒1.5/3 = 1/EC
⇒EC = 3/1.5
EC = 3×10/15 = 2 cm
Hence, EC = 2 cm.
(ii) Given, in △ ABC, DE∥BC
∴ AD/DB = AE/EC [Using Basic proportionality theorem]
⇒ AD/7.2 = 1.8 / 5.4
⇒ AD = 1.8 ×7.2/5.4 = (18/10)×(72/10)×(10/54) = 24/10
⇒ AD = 2.4
Hence, AD = 2.4 cm.
Answered by
1
Answer:
Explanation:
Using Basic proportionality theorem,
∴
DB
AD
=
EC
AE
⇒
3
1.5
=
EC
1
⇒EC=
1.5
3
EC=3×
15
10
=2 cm
EC=2 cm.
(ii) In △ABC,DE∥BC (Given)
Using Basic proportionality theorem,
∴
DB
AD
=
EC
AE
⇒
7.2
AD
=
5.4
1.8
⇒AD=1.8×
5.4
7.2
=
10
18
×
10
72
×
54
10
=
10
24
⇒AD=2.4cm
So, AD=2.4 cm
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