Question

1. In figure1.55, 2 ABC=75°,
Z EDC = 75° state which two triangles
are similar and by which test? Also
write the similarity of these two
triangles by a proper one to one
correspondence.​

Answer 1

Answer:

Δ ABC  ≅  Δ EDC
AC/EC  = BC/DC= AB/ED
 
Step-by-step explanation:

in Δ ABC,
∠ABC = 75 °
∠BCA = x °
∠BAC = 180° - 75° - x° = 105 - x°

in Δ EDC,
∠EDC = 75 °
∠ECD = x °
∠CED = 180° - 75° - x° = 105 - x°

∠ABC = ∠EDC
∠BCA = ∠ECD
∠BAC = ∠CED

All the angles are same so,

Δ ABC  ≅  Δ EDC
AC/EC  = BC/DC= AB/ED