Question

the nth term of an AP is given by an= 3 + 4n . what is the common difference? please its urgent​

Answer 1

Answer:

4

Step-by-step explanation:

Let n be 1

First term: 3+4= 7

Let n be 2

second term: 3 + 4(2) = 11

Similarly you get 15, 19

common difference = 4

Answer 2

Given:

The nth term of an AP is given by an= 3 + 4n.

To find:

The common difference.

Solution:

As given, we have,

The nth term of an A.P. is given by:

an= 3 + 4n

So,

When n = 1,

the first term of the A.P. or a

$= 3 + 4(1)$

$= 3 + 4$

$= 7$

Now,

When n = 2,

the second term of the A.P. or a2

$= 3 + 4(2)$

$= 3 + 8$

$= 11$

Similarly,

the third term of the A.P. or a3

$= 3 + 4(3)$

$= 3 + 12$

$= 15$

So,

the A.P. is 7, 11, 15,...

Now,

the common difference or 'd'

$= a2 - a$

$= 11 - 7$

$= 4$

Hence, the common difference is 4.