Question

1. In sulphur estimation 0.157g of an organic compound gave 0.4813 g of BaSo4. What is the percentage of sulphur in the organic compund?

Answer 1

Weight of BaSO4 = 0.4813 g
Molar mass of BaSO4 = 137.3 + 32 + 16×4 = 233.3 g

moles of BaSO4 in 0.4813g = 0.4813/233.3 = 0.002063 moles
weight of sulphur = 0.002063×32 = 0.066g

weight of organic compound = 0.157g
%of sulphur = (0.066/0.157)×100 = 42%

Answer 2

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Weight of BaSO4 = 0.4813 g

Molar mass of BaSO4 = 137.3 + 32 + 16×4 = 233.3 g

moles of BaSO4 in 0.4813g = 0.4813/233.3 = 0.002063 moles

weight of sulphur = 0.002063×32 = 0.066g

weight of organic compound = 0.157g

%of sulphur = (0.066/0.157)×100 = 42%

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