Question

1. In the above question 18, if internal bisector of ZB and ZC intersect
at P, prove that ZPBO = 90° and ZBOC + ZBPC = 180°​

Answer 1

Answer:

In the above question 18, if internal bisector of ZB and ZC intersect

at P, prove that ZPBO = 90° and ZBOC + ZBPC = 180

Explanation:

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Answer 2

Answer:

please refer above picture

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