Math, asked by sarah2969, 1 month ago

1. In the Figure 13.43, given below, ABC is a triangle and MN is parallel to BC. Given AB = 5 cm,
AM : MB = 3 : 2 and NC = 2 cm. Find
(a) AN : NC, (b) AB : BM, (C) AN, (d) Special name of the triangle ABC.​

Answers

Answered by lalitgumber1128
1

Answer:

3:2

5:2

3cm

similar triangles

Step-by-step explanation:

AM:MB=AN:NC

AM:MB=AN:NC=3:2

AM:MB=3:2 LET AM = 3x , MB = 2x

then AB:BM=AB/BM=5x/2x=5/2=5:2

AN:NC=3:2 if NC = 2 cm , then AN = 3 cm

if one line in triangle is parallel to one side of triangle,

then it is property of similar triangles

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