Question

1 in the figure AB is the diameter of the circle. CD is a perpendicular to AB. PA = 3 cm, PB = 2 CM dength of PC ? Area of triangle ABC?​

Answer 1

PC = PD + CD = 15.3 + 11.9 = 27.2

AP × PB = PD × PC

⇒ 30.6 × PB = 15.3 × 27.2

⇒ PB = (15.3 × 27.2)/30.6

⇒ PB = 13.6

Now, AB = AP - PB = 30.6 - 13.6 = 17 cm

Radius of the circle = 17/2 = 8.5 cm