Question

1)In the figure XY is parallel to QR. PX=2cm,QX=4cm PR=9cm?
a)Find PY=YR? b)Find the length of PY.Q?​

Answer 1

Given :-

• In ∆ PQR, XY || QR.
• PX = 2 cm.
• QX = 4 cm.
• PR = 9 cm.

To Find :-

• PY = ?
• YR = ?

Solution :-

we know that,

• Basic proportionality theorem :- If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points then the other two sides are divided in the same ratio .

since XY || PR .

so,

• PX / XQ = PY / YR .

putting values we get,

→ (2/4) = PY/YR

→ 1/2 = PY/YR

→ PY : YR = 1 : 2

now, dividing PR(9 cm) in 1 : 2 , we get,

→ PY = (1/3) * 9

→ PY = 3 cm. (Ans.)

and,

→ YR = (2/3) * 9

→ YR = 6 cm. (Ans.)

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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