Math, asked by answerbolbe, 8 hours ago

(1) In the following figure, if AB | CD, ZAPQ = 70° and ZPRD = 135º, find x, y and z B P. A Z 70* y 135 с O R D lues of Ar and DO​

Answers

Answered by moviesshinchan9
1

Answer:

∠PQR=∠APQ (Alternate angle)

∠PQR=∠APQ (Alternate angle)x=50

∠PQR=∠APQ (Alternate angle)x=50 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlge

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘ +y+53

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘ +y+53 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘ +y+53 ∘ =180

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘ +y+53 ∘ =180 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘ +y+53 ∘ =180 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘ +y+53 ∘ =180 ∘ y=180

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘ +y+53 ∘ =180 ∘ y=180 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘ +y+53 ∘ =180 ∘ y=180 ∘ −103

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘ +y+53 ∘ =180 ∘ y=180 ∘ −103 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘ +y+53 ∘ =180 ∘ y=180 ∘ −103 ∘ =77

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘ +y+53 ∘ =180 ∘ y=180 ∘ −103 ∘ =77 ∘

∠PQR=∠APQ (Alternate angle)x=50 ∘ ∠PRQ+∠PRD=180 ∘ ∠PRQ+127 ∘ =180 ∘ ∠PRQ=180 ∘ −127 ∘ =53 ∘ ∠PQR+∠QPR+∠PRQ=180 ∘ (Angle sum property of trianlgex+y+53 ∘ =180 ∘ 50 ∘ +y+53 ∘ =180 ∘ y=180 ∘ −103 ∘ =77 ∘

Answered by adityapatel57208
2

Answer:

=x+70+135=360

=x+205=360

=x=360-205

=x=155

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