Question

1. In the super market there are five shapkepers Ag B, C, D, E . If shopkaper A sells his 213 of products in a day , & selles 317 of products. Csells 4/5 of product in a day, I sells 5/6 of products in a day and E selles 7/8 of fondentes in a days she sello more. products in a day but seawal ireless and refresent each fraction in the circles and find the largest fraution and the smallert fruition as the denominator of all fractions ​

Answer 1

Answer:

Multiply each no. By 840 as it is the l.c.m.

A=2*840/3

B=3*840/7

C=4*840/5

D=5*840/6

E=7*840/8

Therefore

A=2*280=560

B=3*120=360

C=4*168=672

D=5*140=700

E=7*105=735

Therefore shopkeeper E sold more products The lowest sale is of B

Step-by-step explanation:

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