Question

the end points of the diameter of a circle are (2,4) AND ( -3 ,-1 ) . WHAT IS THE DIAMETER OF THE CIRCLE?​

Answer 1

Answer:

5

Step-by-step explanation:

Answer 2

GIven the end points of the diameter of a circle are (2,4) and( -3 ,-1 ).

If $(x_1,y_1)$ and $(x_2,y_2)$ are the ends of the diameter.

then, $diameter = \sqrt{(x_{2}-x_{1})^2+(y_2-y_1)^2 }$ (by distance formula)

= $\sqrt{(-3-2)^2+(-1-4)^2 }$

= $\sqrt{(-5)^2+(-5)^2 }$

= $\sqrt{25+25 }$

= $\sqrt{50}$

= $5\sqrt{2}$

Therefore, the diameter of the circle is $5\sqrt{2}$.

pls mark as brainleist as it took time to write with math input ;D