Question

1. In trapezium KLMN, KL and MN are parallel sides. A line is drawn, from the point A on KN, parallel to MN meeting LM at B.KN:LM is equal to
(a) KL:NM
(b) (KL + KA): (NM + BM)
(c) (KA-AN): (LB-BM)
(d) KL2: MN2​

Answer 1

Answer:

hello mate here's your answer→(c)

Step-by-step explanation:

in this question we use intercept theorem.

KA:LB=AN:BM=KN:LM

:.KN:LM=(KA:LB)-(AN:BM)=(KA-AN):(LB-BM)

#together_we_go_far❤️