Question

1. In triangle ABC, AB-5 cm, AC -5 cm and angle A = 50°,
then angle B =?​

Answer 1

As we alredy know that the sum of angles of a triangle is 180°.

In iscoles triangle,the two sides are equal.

A=50°

THEN 2x+50=180°

2x=180°-50°=130°

x=130°/2

x=65°

angle A=65°

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Answer 2

Answer:

angle B = 65⁰

Step-by-step explanation:

since ,AB = AC = 5cm. It is an isosceles triangle.

Therefore, angle B = angle C ( In an isosceles triangle the angles opposite to equal sides are also equal )

So , angle A + angle B + angle C = 180⁰ (sum of all angles of a triangle is 180⁰)

50⁰ + angle B+ angle C =180⁰

50⁰ + angle B + angle B = 180⁰ (angle B = angle C)

50⁰ + 2angle B = 180⁰

2angle B = 180⁰ - 50⁰

2angle B = 130⁰

angle B = 130⁰/ 2

angle B = 65⁰

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