Question

1. In which of the following situations, does the list of numbers involved make an arithmetic
progression, and why?
(1) The taxi fare after each km when the fare is +15 for the first km and *8 for each
additional km.​

Answer 1

Answer:

taxi fare for 1km=15

taxi fare for 2km=15+8 =23

taxi fare for 3km=23+8=31

therefore series is, 15,23,31...

Difference between 2nd term and 1st term

=23-15=8

Answer 2

Answer:

We can write the given condition as;

Taxi fare for 1 km = 15

Taxi fare for first 2 kms = 15+8 = 23

Taxi fare for first 3 kms = 23+8 = 31

Taxi fare for first 4 kms = 31+8 = 39

And so on……

Thus, 15, 23, 31, 39 … forms an A.P. because every next term is 8 more than the preceding term.

Step-by-step explanation:

Hope this helps you ✌️