Question

-1 is the zero of polynomial p(x)=ax^3-x^2+a+4. find value of a .

Answer 1

Q -1 is the zero of polynomial p(x) = $ax^3-x^2+a+4$. Find the value of a.

Answer :-

a = 2

Step by step explanation :-

Given :-

$zero$ = -1

Therefore,

x = -1

To Find :-

Value of $a$

Solution :-

Substituting the value of x :-

$ax^3-x^2+a+4$

= $a(-1)^3-(-1)^2+a+4$

= $-a -1 - 1 +4=0$

= $-a-2+4=0$

= $-a=-2$

= $a = 2$

Therefore value of a = 2.