Question

1 kg of ice at zero degree Celsius is mixed with 1 kg of steam at 100 degree Celsius. what is the resulting temperature and composition at equillibrium????????
Plz answer within 2-3 hours!!!!!!!! also plz explain it veryyyyyy well.

Answer 1

I show you structure for this question below how can we treat this type question
for ice (0C) convert to water at constant temperature heat H1=m1L where m1 is mass of ice and L is latent heat of fusion
now again water heated 0 to 100C
H2=m1s100 where s is specific heat capacity
for steam
convert steam into water H3=m2L'
where L' is latent heat of vaporization and m2 is mass of vapour

-> if H1+H2 <H3
final temperature=100C
and let m kg vapour condensed
heat gain=heat loss
mL'=H1+H2
now we find H1=336000j
H2=4200*100=420000j
H3=2256000j
H1+H2 <H3
hence final temperature is 100 degree Celsius
let m kg vapour condensed
m=756000/2256000=756/2256=0.335 kg
now composition is water 1.335kg and vapour (steam) 0.665kg