1 kg piece of copper is drawn into a wire of 1 mm thick and another piece into wire of 2 mm thick. Compare the resistance of these wires.
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as the material of the wire is same so
as per the formula
R = ¶ L /A
Resistance is inversely proportional to area
let R1 is resistance of 1 mm wire
R2 is resistance of 2 mm wire
R1/R2 = L1A2/L2A1
= L1πr2L2/ L2πr1L1
= r2/r1
= 1/1/2
= 2/1
R1:R2 = 2:1
as per the formula
R = ¶ L /A
Resistance is inversely proportional to area
let R1 is resistance of 1 mm wire
R2 is resistance of 2 mm wire
R1/R2 = L1A2/L2A1
= L1πr2L2/ L2πr1L1
= r2/r1
= 1/1/2
= 2/1
R1:R2 = 2:1
nikhilraj2:
is that a right answer..?
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