Question

1 L of N2(g) combines with 3 L of H2(g) to form 2 L of NH3(g) under the same conditions. This law illustrates the :

Answer 1

Given:

1 L of N2(g) combines with 3 L of H2(g) to form 2 L of NH3(g) under the same conditions.

To find:

Illustration of which Law ?

Solution:

The chemical equation is as follows ;

$\boxed{\sf{N_{2}+3H_{2}\overset{\Delta}{\longrightarrow}2NH_{3}}}$

As per the Equation, the statement follows Gay-Lussac's Law of Gaseous Combination.

This law states that the ratio of volume of combining (or reacting) gases can be expressed in the form of whole numbers;

Verification :

Required ratio:

$\sf{ \dfrac{volume \: of \: hydrogen}{volume \: of \: nitrogen} = \dfrac{3\: L}{1\: L} }$

$\sf{ = > \dfrac{volume \: of \: hydrogen}{volume \: of \: nitrogen} = 3 }$

$\boxed{\sf{ = > vol \: of \: H_{2} : vol \: of \:N_{2} = 3 =whole\: no. }}$

[Hence proved]