1. Let p(x) = 2x* – X – x² + 3x + 8.
i) What is the remainder when p(x) is divided by (x - 1)?
ii) What is p(1)?
Answers
Solution :-
What is the remainder when p(x) = 2x - x - x² + 3x + 8 is divided by (x - 1)?
= Fist, Let's find the zero of the polynomial (x - 1) :
=> x - 1 = 0
.°. x = 1
Putting, the value of p(1) in the equation -
= 2x - x - x² + 3x + 8
= 2 × 1 - 1 - 1² + 3 × 1 + 8
= 2 - 1 - 1 + 3 + 8
= 13 - 2
= 11
Hence, the remainder is 11.
The value of p(1) will also be the same (11) since we've already placed the value of x as 1 in p(x).
Additional information :-
- Polynomials are terms which consists of variables and coefficients. Eg :- x² + 2x - 3
- Quadratic equations are equations which are in the form of - ax² + bx + c
Answer:
Solution :-
What is the remainder when p(x) = 2x - x - x² + 3x + 8 is divided by (x - 1)?
= Fist, Let's find the zero of the polynomial (x - 1) :
=> x - 1 = 0
.°. x = 1
Putting, the value of p(1) in the equation -
= 2x - x - x² + 3x + 8
= 2 × 1 - 1 - 1² + 3 × 1 + 8
= 2 - 1 - 1 + 3 + 8
= 13 - 2
= 11
Hence, the remainder is 11.
The value of p(1) will also be the same (11) since we've already placed the value of x as 1 in p(x).
Additional information :-
Polynomials are terms which consists of variables and coefficients. Eg :- x² + 2x - 3
Quadratic equations are equations which are in the form of - ax² + bx + c