Question

1 litre of water at 20 degree celsius is mixed with the same volume of water at 80 degree Celsius the temperature of the mixture will be

Answer 1

$<h2><font color = red > hey there$


let the temperature be
$\gamma$



so,
$\gamma = \frac{80 + 20}{2} = 50$


so, y = 50℃


Hope it helps you

Thanks for asking....



$<b > prabhudutt$