Question

1 litre substance of density 3 g/cc is mixed homogenously with 3 litre another substance of density 2g/cc. Find the density of the mixture [ 1 A) 2.15 B) 2.35 C) 2.25 D) 2.30





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Answer 1

Given : 1 litre substance of density 3 g/cc is mixed homogenously with 3 litre another substance of density 2g/cc.

To Find : the density of the mixture

[ 1 A) 2.15 B) 2.35 C) 2.25 D) 2.30

Solution:

Density = mass / volume

1 litre substance of density 3 g/cc

1 litre = 1000 cc

Hence   Mass =  3 * 1000  = 3 kg

3 litre another substance of density 2g/cc.

=> Mass = 3 * 2 * 1000 = 6 kg

Total Mass = 3 + 6 = 9 kg = 9000 g

Total Volume = 1 + 3 = 4 litre  =   4000 cc

Density of mixture = 9000/4000  = 2.25 g/cc

the density of the mixture is 2.25 g/cc

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Answer 2

Given:

1 litre substance of density 3 g/cc is mixed homogenously with 3 litre another substance of density 2g/cc.

To find:

Density of mixture?

Calculation:

In order to calculate the density of mixture, simply find out the net mass and net volume as follows:

$net \: mass = \rho_{1}( V_{1}) + \rho_{2}(V_{2})$

$\implies net \: mass = (3 \times 1000) + (2 \times 3000)$

$\implies net \: mass = 9000 \: g$

Now, net volume will be :

$net \: volume = 1 + 3 = 4 \: litres = 4000 \: cc$

Now, net density of mixture:

$\rho_{mixture} = \dfrac{9000}{4000} = 2.25 \: g/cc$

So, density of mixture is 2.25 g/cc.