66. Find the mass of 1 m³ of gold in kg when density of gold is 19 g cm-³
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Answer:
sorry I do notknow
Explanation:
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Answer:
mass = 19000 kg
Explanation:
Given: Volume of gold, v = 1 m³
Density of gold, p = 19 g. cm^(-3)
we know that,
mass, m = volume × density
= 1 m³ × 19 g. cm^(-3)
= (1×10²×10²×10² cm³) × 19 g/cm³
= 19000000 g
= 19000 kg
Answer provided by GauthMath.
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