Question

1)   log₅(2X+4) = 2

2)   logx = 1- log(x- 3)

3)   2log₉√x-log₉(6x-1) = 0

4)   logx + log(x-1) = log(3x+12)

5)   log10 - log(7-x) = logx

Answer 1

c is the correct answer 
because phle to logatherim break ho ga us ke bad value ake solve kr do maine kr diya h ans is c 

Answer 2

$1)log_5(2x+4)=2 \\ 5^2=2x+4 \\ x= \frac{21}{2} \\ 2) x^{2} -3x-10=0 \\ (x-5)(x-2)=0 \\ x=5,x=2$
try others own ur own