Question

(1 + m)2 - 4lm
(Hint: Expand (1 + m)? first)​

Answer 1

Answer:(l-m)^{2}

Step-by-step explanation:

$(l+m)^{2}$-4lm=$l^{2}+2lm+m^{2}$-4lm=$l^{2}-2lm+m^{2}$=$(l-m)^{2}$

Answer 2

$( {1 + m)}^{2} - 41m \\ {1}^{2} + {m}^{2} + 2 \times 1 \times m - 41m \\ 1 + {m }^{2} + 2m - 41m \\ {m}^{2} - 39m + 1$