Question

( 1 + m ) ³ + ( 2m + 3n )³ + ( 3n + 41 )³ - 31 ( 1 + m ) ( 2m + 3n ) ( 3n + 41 )​

Answer 1

Question:-

( 1 + m ) ³ + ( 2m + 3n )³ + ( 3n + 41 )³ - 3 ( 1 + m ) ( 2m + 3n ) ( 3n + 41 )

Solution:-

Here,

a = ( 1 + m ) ³

b = ( 2m + 3n )³

c = ( 3n + 41 )³

So, a + b + c

➬1 + m + 2m + 3n + 3n + 41

➬42 + 3m + 6n = 0

Now,

a³ + b³ + c³ - 3abc = 0

( 1 + m ) ³ + ( 2m + 3n )³ + ( 3n + 41 )³ - 31 ( 1 + m ) ( 2m + 3n ) ( 3n + 41 ) = 0

⟹( 1 + m ) ³ + ( 2m + 3n )³ + ( 3n + 41 )³ = 31 ( 1 + m ) ( 2m + 3n ) ( 3n + 41 )

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