1 m³of ice weighs 900kg.what is the weight of a cubical block of ice of side 0.5 m
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Answered by
30
Weight of 1 m^3 of ice = 900 kg
Length of edge of cubical block of ice = 0.5 m
We know that volume of cube is the result we get after we raise the length of edge of cube to three so,
Volume of cubical block of ice = ( Edge of cubical block ) ^ 3
V = ( 0.5 ) ^ 3
V = 0.125 m ^ 3
Volume of cubical block of ice = 0.125 m ^ 3
Since,
1 m^3 of ice weighs 900 kg.
Therefore,
0.125 m ^ 3 of ice will weigh ( 900 * 0.125 ) kg
0.125 m ^ 3 of ice will weigh ( 9 * 1.25 ) kg
0.125 m ^ 3 of ice will weigh 11.25 kg.
Hence,
Weight of cubical block of ice = 11.25 kg
Length of edge of cubical block of ice = 0.5 m
We know that volume of cube is the result we get after we raise the length of edge of cube to three so,
Volume of cubical block of ice = ( Edge of cubical block ) ^ 3
V = ( 0.5 ) ^ 3
V = 0.125 m ^ 3
Volume of cubical block of ice = 0.125 m ^ 3
Since,
1 m^3 of ice weighs 900 kg.
Therefore,
0.125 m ^ 3 of ice will weigh ( 900 * 0.125 ) kg
0.125 m ^ 3 of ice will weigh ( 9 * 1.25 ) kg
0.125 m ^ 3 of ice will weigh 11.25 kg.
Hence,
Weight of cubical block of ice = 11.25 kg
Answered by
35
Answer:
1 m^3 =900 kg
0.5 m^3=0.5 *900
0.125m=0.125*900
Answer is 112.5kg
Step-by-step explanation:
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