Question

1. Magnitude of two rectangular components of
vector 50 m are drawn. If one component has
magnitude 25 m then calculate magnitude of
the other.
(A) 25 m
(B) 50 m
(C) 40 m
(D)43.3 m​

Answer 1

Answer:

d 43.3

Explanation:

$R^{2}$=$A^{2} + B^{2} + 2ABcos theta$

50*50=25*25+B2 +2[A][B]cos90      {cos90=0}

2500-625 =B2

$\sqrt{1875}$=B

43.30=B

Answer 2

Answer:

43.3N

The magnitude of other is 43.3N