Math, asked by nimalamu96gmailcom, 11 months ago

1 man takes 1/3 of the sum of money and another takes 4/5 of what was left .the remainder amounted to Rs60.the original amount of money was​

Answers

Answered by raimalsiyag
0

Step-by-step explanation:

guess money is X

than X/3

left(x-x/3)=3x-x/3=2x/3

:2x/3×4/5=8x/15

than than all over left(x-x/3-8x/15)=15x-5x-8x/15=2x/15

2x/15=60

X=60×15/2

X=30×15

X=450

Answered by windyyork
0

The original amount is Rs. 450.

Step-by-step explanation:

Since we have given that

Part of sum taken by one man = \dfrac{1}{3}

Remaining part of sum = 1-\dfrac{1}{3}=\dfrac{3-1}{3}=\dfrac{2}{3}

Part of remaining sum taken by another man = \dfrac{4}{5}\times \dfrac{2}{3}=\dfrac{8}{15}

so, remaining part left with it would be

\dfrac{1}{5}\times \dfrac{2}{3}=\dfrac{2}{15}

Let the original sum be 'x'.

Remaining amount = Rs. 60

According to question, it becomes,

\dfrac{2x}{15}=60\\\\x=\dfrac{60\times 15}{2}\\\\x=30\times 15\\\\x=Rs.\ 450

Hence, the original amount is Rs. 450.

# learn more:

1 man takes 1/3 of the sum of money and another takes 4/5 of what was left .the remainder amounted to Rs60.the original amount of money was​

https://brainly.in/question/2088430

Similar questions