Question

1 man takes 1/3 of the sum of money and another takes 4/5 of what was left .the remainder amounted to Rs60.the original amount of money was​

Answer 1

Step-by-step explanation:

guess money is X

than X/3

left(x-x/3)=3x-x/3=2x/3

:2x/3×4/5=8x/15

than than all over left(x-x/3-8x/15)=15x-5x-8x/15=2x/15

2x/15=60

X=60×15/2

X=30×15

X=450

Answer 2

The original amount is Rs. 450.

Step-by-step explanation:

Since we have given that

Part of sum taken by one man = $\dfrac{1}{3}$

Remaining part of sum = $1-\dfrac{1}{3}=\dfrac{3-1}{3}=\dfrac{2}{3}$

Part of remaining sum taken by another man = $\dfrac{4}{5}\times \dfrac{2}{3}=\dfrac{8}{15}$

so, remaining part left with it would be

$\dfrac{1}{5}\times \dfrac{2}{3}=\dfrac{2}{15}$

Let the original sum be 'x'.

Remaining amount = Rs. 60

According to question, it becomes,

$\dfrac{2x}{15}=60\\\\x=\dfrac{60\times 15}{2}\\\\x=30\times 15\\\\x=Rs.\ 450$

Hence, the original amount is Rs. 450.

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1 man takes 1/3 of the sum of money and another takes 4/5 of what was left .the remainder amounted to Rs60.the original amount of money was​

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