Math, asked by kdwivedi267, 10 months ago

1. Meena, Reena and Anjum can complete a 19.
piece of embroidery by themselves in 8 hours,
10 hours and 12 hours respectively. They all
start the work together but after 3 hours
Meena and Anjum leave. How long will Reena
take to complete the remaining work?​

Answers

Answered by littlechaps
3

Answer:

7 hrs 2345+3+1=2-126*56969--*

Answered by sanjeevk28012
11

Answer:

The number of hours required by Reena alone to do remaining work is 3 hours and 45 minutes .

Step-by-step explanation:

Given as :

Meena , Reena and Anjum can complete piece of work in 8 hours

So, The work done by Meen = \dfrac{x}{8}

The work done by Reena = \dfrac{x}{10}

The work done by Anjum = \dfrac{x}{12}

Now, Meena and Anjum work for 3 hours

∴  x = 3

i,e The work done by Meena and Anjum for first 3 hours = \dfrac{x}{8} + \dfrac{x}{12}

Or,  The work done by Meena and Anjum for first 3 hours = \dfrac{ 3x + 2x}{24}

or,  The work done by Meena and Anjum for first 3 hours = \dfrac{5x}{24}

or,  The work done by Meena and Anjum for first 3 hours = \frac{5\times 3}{24}

Or, The work done by Meena and Anjum for first 3 hours = \dfrac{5}{8}

Now, The left work is done by Reena alone

So, The left work = 1 - \dfrac{5}{8}

Or, The left work is done by Reena alone = \dfrac{8-5}{8}

Or, The left work is done by Reena alone = \dfrac{3}{8}

Again

So, The number of hours required by Reena alone to do \dfrac{3}{8}the work = \dfrac{x}{10} = \dfrac{3}{8}

Or, \dfrac{x}{10} = \dfrac{3}{8}

Or, x = \frac{3\times 10}{8}

∴  x = 3.75 hours

So,  The number of hours required by Reena alone to do remaining work = 3 hours and 45 minutes

Hence, The number of hours required by Reena alone to do remaining work is 3 hours and 45 minutes . Answer

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