1 ml of H3PO4 was diluted to 250 ml 25 ml this solution required 40 CC of 0.1N -NaOH for neutralization using phenolphthalein as indicator. What is the specific gravity of acid then?
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Answered by
3
Answer:
The specific gravity of acid will be 20
Explanation:
- Equivalents = (Normality x Volume)
Hence the neutralized equivalents = (40x0.10) = 4 ml equivalents.
- Let M = molarity of the acid then,
1 ml means => m moles of acid = (1xM)
New Molarity would be = (1 x (M/250)) = (M/250)
Now 25ml of this soln. we get equal equivalents,
4 = (M/250) x (25x2)
Therefore, M =20
Answered by
2
Answer:
1.33 g/cc
Explanation:
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