Question

1 ml of H3PO4 was diluted to 250 ml 25 ml this solution required 40 CC of 0.1N -NaOH for neutralization using phenolphthalein as indicator. What is the specific gravity of acid then?

Answer 1

Answer:

The specific gravity of acid will be 20

Explanation:

• Equivalents = (Normality x Volume)

Hence the neutralized equivalents = (40x0.10) = 4 ml equivalents.

• Let M = molarity of the acid then,

1 ml means => m moles of acid = (1xM)

New Molarity would be = (1 x (M/250)) = (M/250)

Now 25ml of this soln. we get equal equivalents,

4 = (M/250) x (25x2)

Therefore, M =20

Answer 2

Answer:

1.33 g/cc

Explanation: