Math, asked by riji31, 9 months ago

please solve the question correctly correctly correctly ......don't spam..... ecplanation must....​

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Answered by TheLifeRacer
6

Provement is in this given attachment !

Both solution is same .

Step 01:- Let's assume (1+sin@)(1+sinb)(1+Siny)= (1-sin@)(1-sinb)(1-siny) =k

step 02:- separate them and multiply that .

Step 03:- Then , multiply with the same angle's t- identity like (1+sin@)to (1-sin@) it comes like (1-sin²¢ )

step 04:- then , as we know (1-sin²¢ ) = cos²¢

Then it will be proved .

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Hope it's helpful !

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Answered by Anonymous
2

Answer:

refer to this attachment ✅✅

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