please solve the question correctly correctly correctly ......don't spam..... ecplanation must....
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Provement is in this given attachment !
Both solution is same .
Step 01:- Let's assume (1+sin@)(1+sinb)(1+Siny)= (1-sin@)(1-sinb)(1-siny) =k
step 02:- separate them and multiply that .
Step 03:- Then , multiply with the same angle's t- identity like (1+sin@)to (1-sin@) it comes like (1-sin²¢ )
step 04:- then , as we know (1-sin²¢ ) = cos²¢
Then it will be proved .
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refer to this attachment ✅✅
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