Question

1 mole electron passes through each of the solution of Mgso4,Agno3,Alcl3 .the mole ratio of Mg,Ag and Al deposited are

Answer 1

Explanation:

How much charge is required to reduce (a) 1 mole of Al3+ to Al and (b)1 mole ... Hence, Ag deposited = 108 × 0.4 = 43.2 g ... Mass of cadmium deposited by passing 100/110×10× 60×60