Question

(secA-tanA)^2=1-sinA/1+sinA. prove it
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Answer 1

Answer:

(secA-tanA)²

=(1/cosA - sinA/cosA)²

=(()/cosA)²

=(1 - sinA)²/cosA²

=(1 - sinA)(1 - sinA)/(1 - sinA²)

=(1 - sinA)(1 - sinA)/(1 - sinA)(1 + sinA)

=(1 - sinA)/(1 + sinA)

Step-by-step explanation:

Answer 2

Hence proved
Hope u understand