Question

a number is chosen at random form a first 25 natural numbers find the probability that the number is not a prime?​

Answer 1

Answer:

hello

Step-by-step explanation:

first of all,

A no. is chosen at random from first 25 natural numbers.

Sample space,

S={1, 2, 3, 4,............ 25}

n(s)=25

Getting integer divisible by 3 or 5.

A={3, 6, 9, 12, 15, 18, 21, 24, 5, 10, 20, 25}

n(A)=12

p(A)= n(A)/n(s)=12/25

so the probability is 12/25

HOPE IT HELPS YOU.

Answer 2

Probability will be 0.56

Step-by-step explanation:

We have given first 25 natural numbers which will be  1 to 25

Total number of natural number number from 1 to 25 = 25

Prime numbers are those numbers which are divisible by 1 and itself

Non prime numbers are those numbers which are divisible by also other number rather than 1 and number itself

So non-prime numbers from 1 to 25 are

4,6,8,9,10,12,14,15,16,18,20,21,24,25

So number of non prime number will be = 14

So probability will be equal to $=\frac{14}{25}=0.56$

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