Question

1 mole of carbon is burnt in 16 g of dioxygen . calculate the amount of carbon dioxide produced ​

Answer 1

Answer:0.5

Explanation:

chemical equation for the reaction is:

i) when 1 mole of carbon is burnt in 1 mole(32 g) of air(dioxygen) ,then according to chemical equation (1) 1mole(44 g) of carbon dioxide is produced.

ii) 32g of Oxygen upon heating gives CO2 = 44g

1 g of Oxygen upon heating gives CO2 = 44/32

Therefore 16 g of Oxygen upon heating gives CO2 = 44/32*16 = 22 g

(iii) According to the question, only 16 g of dioxygen is available. It is a limiting reactant. Thus, 16 g of dioxygen can combine with only 0.5 mole of carbon to give 22 g of carbon dioxide.

Answer 2

hi Dear

when 1 mole of C is burnt in 16 g of oxygen

according to question

C + 02 ------> CO2

• first calculate the limiting reagent here O2 is limiting reagent
• so by stochiometry

32 g O2 gives 44 g Co2

1 g O2 gives 44/32 g CO2

16 g will give 22 g CO2.

Hope you understood