1 MOLE OF FERROUS
SULPHATE IS OXIDIZED TO
FERRIC SULPHATE.
CALCULATE THE EQUIVALENT
WEIGHT OF THE FERROUS
ION. (Fe=55.845, O=16. S=32)
1) 55.84
2) 27.92
3) 18.61
4) 111.68
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Answer:
Answer is A(55.84)
Explanation:
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